Page 1286 - MiSUMi 2025
P. 1286

Economy series       Technical Calculation
                  Shock Absorbers



                 Examples of Calculation for Selection
                                Ex.: Pure Inertial Collision (Horizontal Collision without Thrust Force) Ex.: Horizontal Collision with Air Cylinder Thrust Force  Ex.: Soft Stop in the Cylinder Falling
                   Example of Use   V    S     <Collision Conditions>  Air Cylinder  V  S  <Collision Conditions>  m  F  <Collision Conditions>
                                                                       m=30kg
                                                                                               m=15kg
                                               m=25kg
                       and          m          V=0.6m/s    F  m    3   V=0.6m/s                V=0.2m/s
                 Collision Conditions          F=0N     Air Cylinder   N=20 times/min  Air Cylinder  N=10 times/min
                                               N=30 times/min
                                                        Inner Dia.  φ 40 Operating Pressure 0.5MPa  Inner Dia.  φ 25 Operating Pressure 0.5MPa
                                                                                        *  Collision velocity V is actual measurements
                  Collision Velocity V[m/s]  V=0.6m/s  =  25x0.6 2  =4.5J  V=0.6m/s  =  30x0.6 2  =5.4J  V=0.2m/s  =  15x0.2 2  =0.3J
                                                                                         or 1.5~2 times the average speed.
                    Inertial Energy [J]
                                                                                  mxV 2
                                   mxV 2
                                                           mxV 2
                  Absorbed Energy  Temporary Stroke S'[mm] From Fig.1, S'=20mm (Select Fixed type)  From Fig.1, S'=15mm (Select Adjustable type)  From Fig.1, S'=10mm (Select Adjustable type)
                                E1=
                                                        E1=
                                                                                E1=
                                                                 2
                                                            2
                                                                                         2
                                                                                   2
                                    2
                                         2
                       E1
                   Additional Energy [J]
                                                                                Thrust of the cylinder is F=245.4N
                                                        Thrust of the cylinder is F=628.4N
                                E2'=0J
                       E2'
                                                        E2'=FxS'=628.4x0.015=9.4J
                                                                                E2'=(F+mg)xS'=(245.4+15x9.8)x0.01=3.92J
                   Total Energy E'[J] E'=E1+E2'=4.5+0=4.5J
                 Equivalent Mass [kg]  me'=  2xE'  =  2x4.5  =25kg  E’=E1+E2'=5.4+9.4=14.8J  E'=E1+E2'=0.3+3.92=4.22J
                                                           2xE'
                                                                2x14.8
                                                                                        2x4.22
                                                                                   2xE'
                                                        me'=
                                                                                      =
                                                               =
                                                                    =82.2kg
                                                                                            =211kg
                                                                                me'=
                     me'            V 2  0.6 2              V 2  0.6 2              V 2  0.2 2
                                Select Adjustable type  Select Adjustable type  Select Adjustable type
                                                  Stroke
                                                                          Stroke
                                                                                                  Stroke
                 Temporary selection  Select C-AC1210L from E and me'. ( S=10mm)  Select Medium Speed M from the collision velocity.  ( S=16mm)  Select MAC1612S from E' and me'. ( S=12mm)
                                                                                Select Ultra Low Speed S from Fig. 2.
                                Select L from the collision velocity.
                                                        Select C-AD2016 from E' and me'.
                    Recalculation  E2=0J     me=  2xE  =25kg  E2=FxS=10.1J  me=  2xE  E2=(F+mg)xS=4.71J  me=  2xE  =250kg
                                                                        V 2 =86.1kg
                                E=E1+E2=4.5J    V 2     E=E1+E2=15.5J           E=E1+E2=0.3+4.71=5.01J  V 2
                  Energy per Minute ET  ET=ExN=4.5x30=135J/min  ET=ExN=15.5Jx20=310J/min  ET=ExN=5.01x10=50.1J/min
                    Confirmation  E, me, N and ET are OK.  E, me, N and ET are OK.  E, me, N and ET are OK.
                                                        Select C-AD2016
                                                                                Select MAC1612S* 2
                                Select C-AC1210L
                 * For horizontal collision without thrust force, select the orifice type only by collision velocity.              *2 MAC1612S is not Economy series
                                Ex.: Horizontal Collision with Belt Conveyor Thrust Force Ex.: Collision with synchronous motor driven load Ex.: Horizontal Collision with Belt Conveyor Thrust Force
                                                                       <Collision Conditions>
                                    V  S       <Collision Conditions>  R  m=1kg                <Collision
                                                                       R=0.4m
                   Example of Use  μ  m        m=5kg        r  m   H   r=0.3m      r  R        Conditions>
                                                                       φ =20°
                       and                     V=0.5m/s   M        S   N=10 times/min    S     l=125.5kgm 2
                                                                                               =1.8rad/s
                                               N=20 times/min
                                                                        4
                 Collision Conditions                   Motor Output P=20w, No. of Poles M=36  l= - mr 2 =0.12kgm 2  R=1.25m
                                                                        3
                                                                       =5.6rad/s
                                                        Power Supply Frequency f=50Hz,    F=59.3N  N=6 times/min
                                Dynamic Friction Coefficient µ=0.4  Deceleration Ratio K=20    T=68.6Nm
           17     Collision Velocity V[m/s]  V=0.5m/s  =  5x0.5 2  =0.625J  V=R =0.4x5.6=2.24m/s  =1.88J  V=R =1.25x1.8=2.25m/s =203.31J
                    Inertial Energy [J]
                                                           I
                                                                                   I
                                   mxV 2
                                                            2
                                                               0.12x5.6 2
                                                                                    2
                                                                                       125.5x1.8 2
                  Absorbed Energy
                                                                                E1=
                                                              =
                                                        E1=
                                                                                      =
                                E1=
                                                                                         2
                                                                                   2
                                    2
                                                            2
                                                                 2
                                         2
            Shock Absorbers / Rod End Bearing /   Floating Joints / O-Rings  Equivalent Mass [kg]  E2'=F .  S'=19.6x0.005=0.098J  From Fig.1, S'=10mm (Select Adjustable type)  From Fig.1, S'=50mm (Select Adjustable type)
                       E1
                   Temporary Stroke S'[mm] From Fig.1, S'=5mm (Select Fixed type)
                                                                                       68.6
                                                                                   T
                   Additional Energy [J] F=µmg=0.4x5x9.8=19.6N
                                                                                    , S'=
                                                                                E2'=
                                                        E2'=(F+mg)xS'=(59.3+1x9.8)x0.01=0.69J
                                                                                          x0.05=2.74J
                       E2'
                                                                                  R
                                                                                       1.25
                                                        E'=E1+E2'=1.88+0.69=2.57J
                   Total Energy E'[J] E'=E1+E2'=0.625+0.098=0.723J
                                                                                E'=E1+E2'=203.31+2.74=206.05J
                                                                2x2.57
                                                                                        2x206.05
                                        2x0.723
                                                           2xE'
                                    2xE'
                                                                                   2xE'
                                me'=
                                            =5.8kg
                                                                                             =81.4kg
                                                        me'=
                                                                                me'=
                                                                2.24 2 =1.0kg
                                       =
                                                               =
                                                                                      =
                     me'
                                                                                         2.25 2
                                                            V 2
                                                                                    V 2
                                    V 2
                                         0.5 2
                                                                                Select Adjustable type
                                Select Fixed Type
                                                        Select 2 Stage Type
                                Select Single Orifice from V
                                                        Select Multi-Orifice from Fig. 2.
                                                                                Select MAC3650H from E' and me'. ( S=50mm )
                                                  Stroke
                                                                          Stroke
                                                                                  T
                                                        E2=0.69J
                                E2=E2'=0.098J
                                                2xE
                                                                                E2=
                                                                                   , S=2.74J
                    Recalculation
                                                   =5.8kg
                                             me=
                                                                                            me=
            Shock   Absorbers  Temporary selection  Select C-AC0806L from E' and me'. ( S=6mm )  Select C-AC1210S from E' and me'. ( S=10mm )  Select Speed H Type from Fig. 2.  2xE' Stroke
                                                                     me=1.0kg
                                                                                                   =81.4kg
                                                                                  R
                                                V 2
                                                                                                V 2
                                E=E1+E2=0.723J
                                                        E=E1+E2=2.57J
                                                                                E=E1+E2=206.05J
                  Energy per Minute ET
                                                        ET=ExN=2.57x10=25.7J/min
                                ET=ExN=0.723x20=14.46J/min
                                                                                ET=ExN=206.05x6=1236.3J/min
                                Select C-AC0806L
                                                        Select C-AC1210S
                                                                                Select MAC3650H* 2
          P.17-003  Confirmation  E, me, N and ET are OK.  E, me, N and ET are OK.  E, me, N and ET are OK.
                                                                                *2 MAC3650H is not Economy series
                 QShock Absorbers (P.17-008~P.17-013) Classification according to Absorption Characteristics Structures
            Rod End   Bearings  Structure  Type   Single orifice structure has the same resistance properties as forms of a dashed pot structure
                                                  with a space between the piston and cylinder tube, a single tube structure with an orifice in
          P.17-012  Single Orifice  Fixed / Adjustable  the piston, and a double tube single orifice structure.  F
                                                  Ex. Description of a single tube structure.
                                                  A piston with a single orifice slides into an oil-filled cylinder tube. Because the office area is
                                                  constant over the entire stroke, as the shock absorption characteristics shown in the right
            Floating   Joints                     graph, the resistance is the largest immediately after a collision but gradually reduces speed   S
                                                  as the stroke continues.
                                                  In this double-tube structure, the piston slides in the inner tube. This inner
                           Adjustable
                                                  energy but energy depending on various purposes can be absorbed. It is
          P.17-014  Irregular Multi  Orifice   Heavy Load  tube has several orifices along the direction of strokes, and not only constant   F
                                                  designed to absorb kinetic energy during the first half of stroke and control
                                                  speed during the second half. Therefore, it is well suited to absorb energy
             O-Rings                              against air cylinder thrust.                      S
                    Multi Orifice                 area becomes small gradually as the stroke speed slows down, drag remains
                                                  tube has several orifices along the direction of strokes. Because the orifice
          P.17-015       2 Stage / 2 Way          In this double-tube structure, the piston slides in the inner tube. This inner   F
                                                  largely constant, though the drag fluctuates like a ripple.
          17-007  E  For Adjustable-Dumping Type with thread sizes from M14 to M36 have a single-hole orifice structure, while M42* has an irregular  S                                                        17-008
                   multi-hole orifice structure. *M42 Adjustable type is not Economy series Products.
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